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y=y^2/1+y^2
We move all terms to the left:
y-(y^2/1+y^2)=0
Domain of the equation: 1+y^2)!=0We get rid of parentheses
We move all terms containing y to the left, all other terms to the right
y^2)!=-1
y!=-1/1
y!=-1
y∈R
-y^2/1-y^2+y=0
We multiply all the terms by the denominator
-y^2-y^2*1+y*1=0
We add all the numbers together, and all the variables
-1y^2-y^2*1+y*1=0
Wy multiply elements
-1y^2-1y^2+y=0
We add all the numbers together, and all the variables
-2y^2+y=0
a = -2; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-2)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-2}=\frac{-2}{-4} =1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-2}=\frac{0}{-4} =0 $
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